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tentukan hasil dari
[tex] \frac{9x {}^{4}y }{16xy {}^{3} } \div \frac{2x}{3y} [/tex]
pensi :)![]()
tentukan hasil dari
[tex] \frac{9x {}^{4}y }{16xy {}^{3} } \div \frac{2x}{3y} [/tex]
pensi :)
Materi : Bentuk Aljabar
( 9x⁴y )/( 16xy³ ) ÷ ( 2x )/( 3y )
= ( 9x⁴y )/( 16xy³ ) × ( 3y )/( 2x )
= ( 27x⁴y² )/( 32x²y³ )
= 27x²/32y
Semoga bisa membantu
[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
Jawab:
Penjelasan dengan langkah-langkah:
[tex]\displaystyle \frac{9x^4y}{16xy^3} \div \frac{2x}{3y} = \dfrac{9}{16}\cdot x^{4-1}y^{1-3}\cdot\frac{3y}{2x}\\\frac{9x^4y}{16xy^3} \div \frac{2x}{3y} = \dfrac{27}{32}\cdot x^{3-1}y^{-2+1}\\\\\boxed{\boxed{\frac{9x^4y}{16xy^3} \div \frac{2x}{3y} = \dfrac{27x^2}{32y}}}[/tex]
[answer.2.content]
